Submission Details
lexer98`s SuperPi - 1M Ergebnis
- Enthusiast League
32sec 360ms mit AMD Sempron 3000+ (S754, Palermo) at 2860MHz
Ranglisten Position
n.a.
Globale Rangliste
18th
Sempron 3000+ (S754, Palermo) Rang:
18th von 73
Points earned for overclocker league
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Globale Punkte (UGP)
Not lexer98's best submission
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Hardware Punkte (UHP)
18th mit Sempron 3000+ (S754, Palermo)
26.4 Punkte
Points earned for team league
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Globale Team Power Punkte (GTPP) Not Enthusiasts of Argentina's best submission
0.0 Punkte
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Hardware Team Power Punkte (HTPP) 16th Im Team verwendet Sempron 3000+ (S754
4.2 Punkte
Hardware Details
CPU Details
- Model: AMD Sempron 3000+ (S754, Palermo) 'Palermo-128'
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Kühlung:
Water (Custom)
- Temperatur (°C): 35 Last25 Leerlauf
- Cores: 2.860Mhz(+58.89%)
Arbeitsspeicher Details
- Manufacturer: OCZ Technology
- Produkt: Platinum
- Kühlung: Air (Stock)
- Typ: 512MB DDR SD-RAM
- Geschwindigkeit: @ 318Mhz
- Timings: CL2.5 3-3-8 1T
VGA Details
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- Model: GeForce FX 5200 (NV34) NVIDIA
- Kühlung: Air (Stock)
- Geschwindigkeit: 250Mhz / 200Mhz (Bestand)
Mainboard Details
- Model: K8Upgrade-NF3
- Kühlung: Air (Stock)
- Chipsatz: nForce 3 250
Neueste Kommentare
>Increased VRM frequency >Vdimm vmod >Vcore mod
Nice done Mods, can you please describe how you made the vdimm mod? And how much voltage you can generate?
sagt:
90% volt mods is to connect a resistor between FB pin (feedback) and ground. Sometimes there is a linear voltage regulator op-amp based, so you try whichever in- pin (there are 'in+', 'in-' and 'out' pins) to ground resistor. For example many socket A AsRock motherboards had LM358 as the part of NB voltage. Very often configuration is 3V3 rail -> mosfet (op-amp driven), so max VDIMM should be at least 3,1 Volt (resistance etc.).
thanks for your very quick response!
I know feedback mods, i indentified the LM324 as vDimm Controller but was confused about the Datasheet because there is no FB-Pin, so thanks for your description.
I think i found a post of Lexer https://www.overclock.net/threads/the-socket-939-appreciation-club-and-knowledgebase-official.293448/page-1436#post-26399454
Am I right, that he used Pin 9 (Input 3-) to Pin 11 (GND)?
Just for understanding:
- Should it work to another GND-Point too?
- the other Input/Output curcuits (input 1/2/4) can be other voltages (vDD or something) or not used?
- if i modify that Input voltage to 5V instead of 3V3 Rail, can it work higher than 3,1V or i will fire it up? 3,0V is enough for my TCCD, only for research
sagt:
Am I right, that he used Pin 9 (Input 3-) to Pin 11 (GND)?
~Looks like this, considering "ST" logo and the middle GND pin.
- Should it work to another GND-Point too?
~Yes, but the closest is best (there is sometimes GND, Power-GND, Analog GND, so to be shure I recommend to connect to 2cm/1inch "as close as possible")
- the other Input/Output curcuits (input 1/2/4) can be other voltages (vDD or something) or not used?
~yes, I remember AsRock had AGP, vDimmRef, vNB, vDimm on one quad-op amp like LM324, impressive
- if i modify that Input voltage to 5V instead of 3V3 Rail, can it work higher than 3,1V or i will fire it up? 3,0V is enough for my TCCD, only for research
~in this configuration almost always the power componnent is a power SMD transistor. If your mems eat 1Amp or 2 amps, and vMem is 2.5, from 3V3 rail, the power dissapated on transistor is 3.3-2.5 over 1 Amp is (I=U/R so 3.3-2.5 is 0.8 x 1 is 0.8 W, it's not huge, but if you run full load, the current might jump to few amps) So 1A from 3.3V is 0.8W and from 5V is 5-2.5 x 1 = 2.5 W. This makes huge power losses and hot transistor.
i did this mod as seen in the picture (before you confirmed that) and works great, thanks!
i asked because i only can go up to ~292Mhz BusSpeed, maybe need to try another CPU, because other guys get 320+ without vNB Mod.
mhh i think i dont get it fully.
the differenz from input and Output voltage multiply by Output current = power dissapated of transistor?
then for example, a RAM about 2,5V and 1A @Stock:
vDimm 2,5V/1A=2,5Ohm @5V Rail = (5V-2,5V)*1A = 2,5W dissipation as you wrote
but if i need 3.5V for same RAM Typ
vDimm 3,5V/2,5Ohm=1,4A @5V Rail = (5V-3,5V)*1,4A = 2,1W dissipation?
with higher Voltage and higher Current less dissipation, i think there is a mistake in calculation.
sagt:
P=u*u/r or p=i*i*r, my mistake!
So its even worse because voltage diff is squared. Ehh electronic engineer doesnt remember ohms law... ?
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